VF_mulMT VD_mulMT VE_mulMT
Functionmultiply a row vector by the transpose of a matrix
Syntax C/C++#include <MFstd.h>
void VF_mulMT( fVector Y, fVector X, fMatrix MA, ui htA, ui lenA );
C++ MatObj#include <OptiVec.h>
void vector<T>::mulMT( const vector<T>& X, const matrix<T>& MA );
Pascal/Delphiuses MFstd;
procedure VF_mulMT( Y, X:fVector; MA:fMatrix; htA, lenA:UIntSize );
CUDA function C/C++#include <cudaMFstd.h>
int cudaVF_mulMT( fVector d_Y, fVector d_X, fMatrix d_MA, ui htA, ui lenA );
void VFcu_mulMT( fVector h_Y, fVector h_X, fMatrix h_MA, ui htA, ui lenA );
CUDA function Pascal/Delphiuses MFstd;
function cudaVF_mulMT( d_Y, d_X:fVector; d_MA:fMatrix; htA, lenA:UIntSize ): IntBool;
procedure VFcu_mulMT( h_Y, h_X:fVector; h_MA:fMatrix; htA, lenA:UIntSize );
DescriptionY = X * MAT
The dimensions htA and lenA refer to the original (rather than the intermediate transposed) matrix MA; the dimensions of X and Y are implicitly given by the matrix dimensions: sizX = lenA, sizY = htA.
See alsoVF_mulM,   MF_mulV,   chapter 9

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