| VF_mulMT
| VD_mulMT |
VE_mulMT |
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| Function | multiply a row vector by the transpose of a matrix |
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| Syntax C/C++ | #include <MFstd.h>
void VF_mulMT( fVector Y, fVector X, fMatrix MA, ui htA, ui lenA ); |
| C++ MatObj | #include <OptiVec.h>
void vector<T>::mulMT( const vector<T>& X, const matrix<T>& MA ); |
| Pascal/Delphi | uses MFstd;
procedure VF_mulMT( Y, X:fVector; MA:fMatrix; htA, lenA:UIntSize ); |
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| CUDA function C/C++ | #include <cudaMFstd.h>
int cudaVF_mulMT( fVector d_Y, fVector d_X, fMatrix d_MA, ui htA, ui lenA );
void VFcu_mulMT( fVector h_Y, fVector h_X, fMatrix h_MA, ui htA, ui lenA );
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| CUDA function Pascal/Delphi | uses MFstd;
function cudaVF_mulMT( d_Y, d_X:fVector; d_MA:fMatrix; htA, lenA:UIntSize ): IntBool;
procedure VFcu_mulMT( h_Y, h_X:fVector; h_MA:fMatrix; htA, lenA:UIntSize );
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| Description | Y = X * MAT
The dimensions htA and lenA refer to the original (rather than the intermediate transposed) matrix MA; the dimensions of X and Y are implicitly given by the matrix dimensions: sizX = lenA, sizY = htA. |
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